Covalent bonds in a molecule absorb radiation in the IR region and vibrate at characteristic frequencies. (a) A molecular vibration absorbs radiation of wavelength 194 μm. What frequency (in s−1) corresponds to that wavelength? Enter your answer in scientific notation. × 10 s−1 (b) A molecular vibration has a frequency of vibration of 1.409 × 1013 Hz. What wavelength (in μm) corresponds to that frequency?

Respuesta :

Answer:

(a) Frequency will be equal to [tex]1.718\times 10^{11}s^{-1}[/tex]

(b) Wavelength will be equal to [tex]21.4\mu m[/tex]      

Explanation:

Velocity of light [tex]=3\times 10^8m/sec[/tex]

(A) We have given wavelength of light [tex]\lambda =194\mu m=194\times 10^{-6}m[/tex]

We have to find frequency corresponding to this wavelength

We know that velocity of light is equal to [tex]v=\lambda f[/tex]

[tex]f=\frac{v}{\lambda }=\frac{3\times 10^8}{194\times 10^{-6}}=1.718\times 10^{11}Hz[/tex][tex]=1.718\times 10^{11}s^{-1}[/tex]

(b) We have given frequency of vibration [tex]f=1.40\times 10^{13}s^{-1}[/tex]

We have to find wavelength corresponding to this frequency

We know that velocity of light is equal to [tex]v=\lambda f[/tex]

[tex]\lambda =\frac{v}{f}=\frac{3\times 10^8}{1.40\times 10^{13}}=2.14\times 10^{-5}m=21.4\mu m[/tex]