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A boy with a mass of 30kg rides a merry-go round with a radius of 1.5 meters and a velocity of 0.38 m/s. What is the centripetal force on the boy? __N

Respuesta :

afzbyjus

Answer:

The centripetal force on the boy = 2.888 N

Explanation:

Given:

m = 30 kg

r = 1.5 m

v = 0.38 m/s

To Find:

The centripetal force on the boy = ?

Solution:

F = m x v^2 / r

F = 30 kg x (0.38 m/s)^2 / 1.5 m

F = 30 x 0.1444 / 1.5

F = 2.888 N

Therefore,

The centripetal force on the boy = 2.888 N

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samueladesida43

The centripetal force of the boy with a mass of 30kg who rides a merry-go round with a radius of 1.5 meters and a velocity of 0.38 m/s is 2.89N

CENTRIPETAL FORCE:

  • The centripetal force of the boy can be calculated by using the following formula:

  • F = m. v²/r

Where;

  1. m = mass of the boy (kg)
  2. v = velocity (m/s)
  3. r = radius of the merry go round (m)

  • According to this question, a boy with a mass of 30kg rides a merry-go round with a radius of 1.5 meters and a velocity of 0.38 m/s, the centripetal force can be calculated as follows:

F = (30 × 0.38²) ÷ 1.5

F = 4.332 ÷ 1.5

F = 2.89N

  • Therefore, the centripetal force of the boy with a mass of 30kg who rides a merry-go round with a radius of 1.5 meters and a velocity of 0.38 m/s is 2.89N.

Learn more at: https://brainly.com/question/22976254?referrer=searchResults

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