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Many flashlights are powered by a stack of batteries that are slid into the end of the flashlight one after another. Suppose you have a flashlight that takes four ideal 1.5 V batteries. If the resistance of the bulb is 11 ohms, what is the current through the bulb when the flashlight is turned on

Respuesta :

Answer:

The current through the bulb when the flashlight is turned on is 0.55 A.

Explanation:

Given that,

You have a flashlight that takes four ideal 1.5 V batteries, voltage of the flashlight, V = 6 V

The resistance of bulb, R = 11 ohms

We need to find the current through the bulb when the flashlight is turned on. As per Ohms's law :

V = IR

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{6\ V}{11\ \Omega}\\\\I=0.55\ A[/tex]

So, the current through the bulb when the flashlight is turned on is 0.55 A. Hence, this is the required solution.                

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