A) The moment of inertia of the rod with respect to a parallel axis through one end of the rod is; I_end = ¹/₃mL²
B) The moment of inertia about an axis p through one of the edges of the cube is; I_edge = ²/₃ma²
We are given the formula for the moment of inertia of the same object about a parallel axis passing through point p using parallel axis theorem as;
I_p = I_cm + Md²
where;
d is the perpendicular distance from the center of mass to the axis that passes through point p
M is the mass of the object
I_cm is the moment of inertia of an object about an axis passing through its center of mass
A) We are told that;
Length = L
Mass = m
I_cm = ¹/₁₂mL²
We want to find I_end, the moment of inertia of the rod with respect to a parallel axis through one end of the rod.
This means that d = L/2. Thus;
I_end = ¹/₁₂mL² + m(L/2)²
I_end = ¹/₁₂mL² + ¹/₄mL²
I_end = ¹/₃mL²
B) We want to find I_edge, the moment of inertia about an axis p through one of the edges of the cube.
We are told that;
I_cm = ¹/₆ma²
Edge length is a. Thus;
d = a/√2
Thus;
I_edge = ¹/₆ma² + m(a/√2)²
I_edge = ¹/₆ma² + ¹/₂ma²
I_edge = ²/₃ma²
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