Answer:
[tex]F =K \frac{q_{1}q_{2} }{(d-R)^{2} }[/tex]
Explanation:
According to Coulomb's law, the force of attraction between two charges, q1 and q2 is directly proportional to the product of the charges and inversely proportional to the distance separating them.
[tex]F =K \frac{q_{1}q_{2} }{d^{2} }[/tex]
Since d > R
the second charge will experience a force [tex]F =K \frac{q_{1}q_{2} }{(d-R)^{2} }[/tex]
Where K = 9.0 x 10⁹ N.m²/C²
