The 30th term of the given linear sequence is -63 and this can be determined by using the nth term formula of the arithmetic operation.
Given :
Sequence --- -5,-7,-9,-11,-13,...
The given sequence is in arithmetic progression whose difference is given by:
[tex]\rm a_2-a_1 = d[/tex]
-7 - (-5) = d
d = -2
The nth term in the arithmetic progression is given by the formula:
[tex]\rm T_{n} = a + (n-1)d[/tex]
where 'n' is the number of terms, 'a' is the first term, [tex]\rm T_n[/tex] is the nth term, and 'd' is the difference.
Now, substitute the known terms in the above formula.
[tex]\rm T_{30} = -5 + (30-1)\times -2[/tex]
[tex]\rm T_{30} = -5 + (29)\times -2[/tex]
[tex]\rm T_{30} = -5 - 58[/tex]
[tex]\rm T_{30} = - 63[/tex]
So, the 30th term of the given linear sequence is -63.
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https://brainly.com/question/16764034
