pls pls pls help for points

Answer:
see below
Step-by-step explanation:
g(x) = (x+2)^2 -1
The function is in the form
g(x) = a(x-h)^2 +k
where (h,k) is the vertex of the parabola
Rewriting
g(x) = (x+2)^2 -1
= (x--2)^2 + -1
The vertex is (-2,-1)
We can find another point by letting x =0
g(0) = (0+2)^2 -1
=2^2 -1
=4-1 =3
The second point is (0,3)
Answer:
Vertex: (-2,-1)
y - intercept: 3
x - intercepts: -1 and -3
Step-by-step explanation:
Vertex would be at: (-2,-1)
And the y - intercept would be 3
y = (0+2)² - 1 = 3
0 = (x+2)² - 1
(x+2)² = q
x = 1 - 2 = -1
x = -1 - 2 = -3