Answer:
y = w and ΔABC ~ ΔCDE
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90°  ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
∴ ∠x = ∠z
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
∴ ∠y = ∠w
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C  ⇒ proved by ∠y = ∠w
- ∠B = ∠D  ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E  ⇒ proved by ∠x = ∠z
So, from the previous  ΔABC ~ ΔCDE by AAA postulate.
So, the answer is y = w and ΔABC ~ ΔCDE