Answer:
3.97× 10²³ atoms of Ag
Explanation:
Given data:
Mass of Ni = 112 g
Mass of AgNO₃ = 112 g
Atoms of silver produced = ?
Solution:
Chemical equation:
Ni + 2AgNO₃ → 2Ag + Ni(NO₃)₂
Number of moles of Ni:
Number of moles = mass/ molar mass
Number of moles = 112 g/58.7 g/mol
Number of moles = 2 mol
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 112 g/169.87 g/mol
Number of moles = 0.66 mol
Now we will compare the moles of Ag with both reactants.
AgNO₃ : Ag
2 : 2
0.66 : 0.66
Ni : Ag
1 : 2
2 ; 2×2= 4 mol
Number of moles of Ag produce by AgNO₃ are less so it will limiting reactant and limit the yield of Ag.
I mole = 6.022 × 10²³ atoms
0.66 mol × 6.022 × 10²³ atoms / 1 mol
3.97× 10²³ atoms of Ag
