Respuesta :
A string parameter and returns new string with all the letters of the alphabet that are not in the argument string. The letters in the returned string should be in alphabetical order. The implementation should uses a histogram from the histogram function
Explanation:
The below code is written in python :
alphabet = "abcdefghijklmnopqrstuvwxyz"
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]
def histogram(s):
d = dict()
for c in s:
if c not in d:
d[c] = 1
else:
d[c] += 1
return d
def has_duplicates(s):
for v in histogram(s).values():
if v > 1:
return True
return False
def test_dups_loop():
for s in test_dups:
print(s + ':', has_duplicates(s))
def missing_letters(s):
r = list('abcdefghijklmnopqrstuvwxyz')
s = s.lower()
for c in s.lower():
if c in r:
r.remove(c) # the first matching instance
return ''.join(r)
def test_miss_loop():
for s in test_miss:
print(s + ':', missing_letters(s))
def main():
test_dups_loop()
test_miss_loop()
if __name__ == '__main__':
main()
The program illustrates the use of lists and iterations.
Lists are used to hold multiple values in one variable, while iterations are used for repetitive operations
The missing_letter function written in Python, where comments are used to explain each line is as follows:
#This initializes the alphabet
alphabet = "aefghijklrstuvwxyz"
#This defines the missing_letters function
def missing_letters(s):
#This creates a list of alphabet
r = list('abcdefghijklmnopqrstuvwxyz')
#This iterates through the string
for c in s.lower():
#This iterates through the list
if c in r:
# This removes the present letters
r.remove(c)
#This returns the missing letters
return ''.join(r)
print(missing_letters(alphabet))
Read more about lists and iterations at:
https://brainly.com/question/18917298