The following standing wave below is a 5 m string that vibrates up and down as the four harmonic (4 bumps). The string vibrates 48 cycles in 16 seconds. Determine the string’s speed

Respuesta :

Answer:

7.5 m/s

Explanation:

Standing waves are waves that do not propagate, so they are just oscillations of the medium over fixed positions.

Standing waves are produced for example in a string, which is tied at its ends.

The wavelength of the fundamental mode of vibration of a string is equal to twice the length of the string:

[tex]\lambda=2L[/tex]

where L is the length of the string.

Here, the string vibrates in its fourth harmonic - this means that the wavelength is actually 1/4 of the wavelength of the fundamental mode:

[tex]\lambda_4=\frac{\lambda}{4}[/tex]

Here, the length of the string is

L = 5 m

So the wavelength of the 4th harmonic is:

[tex]\lambda_4=\frac{\lambda}{4}=\frac{2L}{4}=\frac{2(5)}{4}=2.5 m[/tex]

The frequency of the wave is equal instead to the ratio between the number of cycles and the time taken:

[tex]f=\frac{N}{t}[/tex]

where here

N = 48

t = 16 s

Substituting,

[tex]f=\frac{48}{16}=3 Hz[/tex]

Now we can find the string's speed by using the wave equation; we find:

[tex]v=f\lambda=(3 Hz)(2.5 m)=7.5 m/s[/tex]