Answer:
On wire A the speed is 684 m/s
On wire B the speed is 456 m/s
Explanation:
The velocity of a wave is defined as wavelength times frequency of the wave:
[tex]v= \lambda f [/tex] (1)
with λ the wavelength and f the frequency of the wave.
When you have a wire stretched between two fixed supports, you're going to have standing waves if you perturbate the wire, and the wavelength of the different harmonics you can have is:
[tex]\lambda_m=\frac{2L}{m} [/tex]
with L the length of the wire and m the number of the harmonic, so for the second harmonic:
[tex]\lambda_2=\frac{2(1.5)}{2}=1.5m [/tex]
ad for the third harmonic:
[tex]\lambda_3=\frac{2(1.5)}{3}=1.0m [/tex]
Using those values of wavelength on (1):
For second harmonic:
[tex]v_A=\lambda_2 f_A=1.5*456=684\frac{m}{s} [/tex]
For third harmonic:
[tex]v_A=\lambda_3 f_A=1.0*456=456\frac{m}{s}[/tex]
Answer:
Explanation:
Given:
Length, L = 1.5 m
Frequency, f = 456 Hz
Velocity, v = frequency, f × wavelength, λ
At the second harmonic,
f = 2 × (v/2L)
v = 456 × 1.5
= 684 m/s
At the third harmonic,
f = 3 × (v/2L)
Where,
v = velocity
v = 2/3 × 456 × 1.5
= 456 m/s
