Answer:
156.68 grams of carbon dioxide is produced per [tex]2.50\times 10^3 [/tex] kJ of heat released.
Explanation:
[tex] C_5H_{12}(l) + 8O_2(g)\rightarrow 5CO_2(g) + 6H_2O(l),Delta H_{rxn}^o= -3510 kJ/mol[/tex]
Amount of energy produced = Q = [tex]-2.50\times 10^{3} kJ[/tex]
Let the moles of pentane burnt to produce Q energy be n.
[tex]\Delta H_{rxn}^o\times n= Q[/tex]
[tex]-3150 kJ/mol\times n=-2.50\times 10^{3} kJ[/tex]
[tex]n=\frac{-2.50\times 10^{3} kJ}{-3150 kJ/mol}=0.7122 mol[/tex]
According to reaction, 1 mole of pentane gives 5 moles of carbon dioxide gas, then 0.7122 moles of pentane will give :
[tex]\frac{5}{1}\times 0.7122 mol=3.561 mol[/tex]
Mass of 3.561 moles of carbon dioxide gas :
3.561 mol × 44 g/mol = 156.68 g
156.68 grams of carbon dioxide is produced per [tex]2.50\times 10^3 [/tex] kJ of heat released.
