Answer:
Maximum acceleration will be equal to [tex]3.43m/sec^2[/tex]
Explanation:
We have given coefficient of kinetic friction [tex]\mu _k=0.7[/tex]
And coefficient of static friction [tex]\mu _s=1[/tex]
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
When truck moves maximum force will be equal to [tex]F=\mu _kmg[/tex]
It is given that half of the weight is supported by its drive wheels
So force required [tex]=\frac{\mu _kmg}{2}[/tex]
From newtons law maximum acceleration will be equal to [tex]a=\frac{\frac{\mu _kmg}{2}}{m}=\frac{\mu _kg}{2}=\frac{0.7\times 9.8}{2}=3.43m/sec^2[/tex]
