Respuesta :
The answer for the following problem is explained below.
- Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
Explanation:
Given:
mass of methane = 6.00 × 10^-3 grams
[tex]CH_{4}[/tex] + [tex]O_{2}[/tex] → [tex]CO_{2}[/tex] + [tex]H_{2}O[/tex]
Firstly balance the following equation:
Before balancing the equation:
[tex]CH_{4} + O_{2}[/tex] → [tex]CO_{2} + H_{2} O[/tex]
After balancing the equation:
[tex]CH_{4} + 2O_{2}[/tex] → [tex]CO_{2} + 2 H_{2} O[/tex]
where;
[tex]CH_{4}[/tex] represents methane molecule
[tex]O_{2}[/tex] represents oxygen molecule
[tex]CO_{2}[/tex] represents carbon dioxide molecule
[tex]H_{2}O[/tex] represents water molecule
[tex]CH_{4}[/tex] +2 [tex]O_{2}[/tex] → [tex]CO_{2}[/tex] + 2[tex]H_{2}O[/tex]
16 grams of methane → 44 grams of carbon dioxide
6 × 10^-3 grams of methane → ?
= [tex]\frac{44*6.00*10^{-3} }{16}[/tex]
= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
