Answer: The amount of heat absorbed by the solution is 2.795 kJ
Explanation:
To calculate the mass of water, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of water = 1 g/mL
Volume of water = [70 + 70] = 140 mL
Putting values in above equation, we get:
[tex]1g/mL=\frac{\text{Mass of water}}{140mL}\\\\\text{Mass of water}=(1g/mL\times 140mL)=140g[/tex]
To calculate the heat absorbed, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed
m = mass of water = 140 g
c = heat capacity of water = 4.186 J/g°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(28.74-23.97)^oC=4.77^oC[/tex]
Putting values in above equation, we get:
[tex]q=140g\times 4.186J/g^oC\times 4.77^oC=2795.4J=2.795kJ[/tex]
Hence, the amount of heat absorbed by the solution is 2.795 kJ