contestada

how many moles of sodium hydroxide (NaOH) are required to completely neutralize 2 mol of nitric acid (HNO3)

Respuesta :

2 moles of sodium hydroxide will be needed.

Explanation:

Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.

The reaction between them are

NaOH +HNO3 =NaNO3 +H2O.

So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.

2 moles of sodium hydroxide (NaOH) are required to completely neutralize 2 moles of nitric acid (HNO₃)

Neutralization reaction

From the question, we are to determine number of moles of NaOH required to completely neutralize 2 moles of HNO₃

First, we will write the balanced chemical equation for the neutralization reaction

The balanced chemical equation for the reaction is

HNO₃ + NaOH → NaNO₃ + H₂O

This means, 1 mole of HNO₃ is required to completely neutralize 1 mole of NaOH

Since,

1 mole of HNO₃ is required to completely neutralize 1 mole of NaOH

Then,

2 moles of NaOH will be required to completely neutralize 2 moles of HNO₃

Hence, 2 moles of sodium hydroxide (NaOH) are required to completely neutralize 2 moles of nitric acid (HNO₃)

Learn more on Neutralization reaction here: https://brainly.com/question/25950682