Answer:
[tex]0.052 m^3[/tex]
Explanation:
We can solve this problem by using the ideal gas equation, which states that:
[tex]pV=nRT[/tex]
where
p is the gas pressure
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
In this problem, we have:
n = 2.3 mol of the gas
The gas is in STP condition, so:
T = 273.15 K is the temperature
[tex]p=1.013\cdot 10^5 Pa[/tex] is the pressure
[tex]R=8.31 J/mol K[/tex] is the gas constant
Solving for V, we find the volume:
[tex]V=\frac{nRT}{p}=\frac{(2.3)(8.31)(273.15)}{1.013\cdot 10^5}=0.052 m^3[/tex]
