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Using a 4 mH inductor, design a high-pass, RL, passive filter with a cutoff frequency of 27 krad/s. Part APart complete Specify the value of the resistance. Express your answer to three significant figures and include the appropriate units. R = 108 Ω Previous Answers Correct Part B Assume the filter is connected to a pure resistive load. The cutoff frequency is not to drop below 24 krad/s. What is the smallest load resistor that can be connected across the output terminals of the filter?

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Answer:

Rl≤ 864 ohms

Explanation:

ω=2πf⇒ f=ω/2π

ω=27000

fc=R/2Ï€L

27000/2π= R/(2π×0.004)

R=108 ohms

For terminated RL filters, cutoff frequency is given by

ω=(R || Rl)/ L

24000 ≥ (108 || Rl)/ 0.004

96 ≥ 108Rl/(108+Rl)

Rl≤ 864 ohms

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