Answer:
The answer to your question is below
Explanation:
To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.
Alkanes Cn H(2n + 2)
Alkenes Cn H (2n) "n" is the number of Carbons
Alkynes Cn H (2n - 2)
a) CH₄ C₁ H 2(1) +2 = C₁H₂ + ₂ = CH₄ Alkane
b) C₂H₄ C₂ H₂(₂) Alkene
c) C₃H₆ C(₃) H₂ (₃) Alkene
d) C₂H₂ C₂ H₂(₂) - 2 = C₂H₄ - ₂ = C₂H₂ Alkyne
e) C₁₀H₂₂ C₁₀ H₂(₁₁) Alkene
