Respuesta :
Answer:1.86×10^(-22)seconds
Explanation:
The copper wire has a cross sectional area(CSA) of 0.44cm² and a length of 0.85m......we first need to convert the (CSA) to m² .To do this 0.44cm² is divided by 10000(since 100cm make 1m)..0.44/10000=0.000044m²..
Volume=CSA × length
Volume=0.000044m²×0.85m
Volume(m³)= 0.0000374m³
Therefore, the total charge carriers is the product of the volume and the charge per unit volume
Total charge carriers= 0.0000374m³× 8.48×1028m^(-3)
Total charge carriers= 0.3260charge carriers
Recall however, that the charge per unit charge carrier is 1.60×10^(-19)
Therefore, the total charge on the copper wire is=
1.60×10^(-19)coulombs×0.3260
Total quantity of charge=5.216×10^(-20)coulumbs
And Quantity of charge(Q)= current(I)×time (t)
Time={5.216×10^(-20)}C/280A
Time=1.86×10^(-22)seconds
Answer:
Explanation:
Given:
Current, i = 280 A
Cross-sectional area, A = 0.44 cm^2
Converting from cm^2 to m^2,
0.44 cm^2 × (1 m)^2/(100 cm)^2
= 0.44 × 10^-4 m^2
Length, L = 0.85 m
Number of charge carriers per unit volume, nv = 8.49 ✕ 10^28 m^−3
Current density, J = nv × q × v
I/A = nv × q × v
I = nv × A × q × (L/t)
t = (nv × A × q × L)/I
= (8.49 ✕ 10^28 × 0.44 × 10^-4 × 1.602 × 10^-19 × 0.85)/280
= 1816.7 s
Since 60 seconds = 1 minute
= 30.28 minutes
