Answer:
[tex]3.28*10^{-7}[/tex]
Explanation:
ΔG° = - 8.03 kJ/mol & ΔG = -45.28 kJ/mol
Thus:
Overall ΔG = (- 8.03 + 45.28) kJ/mol
ΔG = 37.25 kJ/mol
ΔG = 37250 J/mol
Temperature = 27 °C
= (27 + 273)K
= 300 K
Therefore :
ΔG = -RTInK
In K = [tex]\frac{\delta G}{RT}[/tex]
In K = Â [tex]\frac{37250}{300*8.314}[/tex]
In K = [tex]\frac{37250}{2494.2}[/tex]
In K = 14. 93
  K = [tex]e^{-14.93}[/tex]
  K = [tex]3.28*10^{-7}[/tex]
the standard free energy of the first reaction at 27 °C = [tex]3.28*10^{-7}[/tex]