Answer:
0.488
Step-by-step explanation:
-Given the probability of success is 20%.
-The events are independent of each other, therefore the probability of being accepted in at least one is equivalent to p=1-P(none)
[tex]p=1-(1-0.2)^3\\\\=\frac{61}{125}=0.488[/tex]
Hence, the probability that she's accepted in at least one is 0.488