Answer:
Check the explanation
Step-by-step explanation:
Since each and every one of the 4 hallways is equally likely then
[tex]P(H1)=1/4P(H2)=1/2P(H3)=1/4[/tex]
Now, if he chooses H1 he escapes after 12 minutes then
[tex]E(T|H1)=12[/tex]
If he chooses H2 then he wastes 10 minutes and then he is again in the same starting
position so he expects to escape in E(T) minutes, then
[tex]E(T|H2)=10+E(T)[/tex]
Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting
position so he expects to escape in E(T) minutes, then
[tex]E(T|H3)=40+E(T)[/tex]
Therefore
[tex]E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'[/tex]
So we have
[tex]E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72[/tex]
Therefore he is expected to escape in 72 minutes