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A total of 1.4 moles of sodium nitrate is dissolved in enough water to make 2.0 liters of an aqueous solution. The gram-formula mass of sodium nitrate is 85 grams per mole. Determine the molarity of the solution. Be sure to include a number and unit in your response.

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Answer:

[NaNO₃] = 0.70 M

Explanation:

Molarity is a type of concentration for solutions. The unit is M but we can also find it as mol/L. It gives us the information about the moles of solute, contained in 1L of solution.

Solute: NaNO₃ → Moles = 1.4

Volume of solution 2L

Molarity = 1.4 mol/2L → 0.70 mol/L

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