. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency of sound played by one of the speakers is 1050 Hz, what is the frequency of sound played by the other speaker

Respuesta :

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

[tex]F_b = |F_1-F_2|[/tex]

Our values are given as,

[tex]F_b = 5Hz[/tex]

[tex]F_1 = 1050Hz[/tex]

Using the formula of the frequency I will have,

[tex]F_b = |F_1-F_2|[/tex]

Replacing we have,

[tex]5 = |1050-F_2|[/tex]

[tex]F_2 = 1050 \pm 5[/tex]

[tex]F_2 = 1045,1055 Hz[/tex]

The possible values are two: 1045Hz and 1055Hz