Answer with Explanation:
We are given that
Mass of squirrel,m=530 g=[tex]\frac{530}{1000}=0.530 kg[/tex]
1kg=1000 g
Area=A=[tex]935 cm^2=935\times 10^{-4} m^2[/tex]
[tex]1 cm^2=10^{-4} m^2[/tex]
Height,h=4.4 m
C=1
[tex]\rho=1.21 kg/m^3[/tex]
Width of rectangular prism,b=11.6 cm=[tex]\frac{11.6}{100}=0.116 m[/tex]
1 m=100 cm
Length,l=23.2 cm=[tex]0.232 m[/tex]
Area=[tex]l\times b=0.116\times 0.232=0.0269 m^2[/tex]
Terminal velocity,[tex]v_t=\sqrt{\frac{2mg}{\rho CA}}[/tex]
Where [tex]g=9.8 m/s^2[/tex]
Using the formula
[tex]v_t=\sqrt{\frac{2\times 0.530\times 9.8}{1.21\times 1\times 0.0269}}[/tex]
[tex]v_t=17.86 m/s[/tex]
The velocity of person,[tex]v=\sqrt{2gh}[/tex]
Using the formula
[tex]v=\sqrt{2\times 9.8\times 4.4}[/tex]
[tex]v=9.29 m/s[/tex]
