Answer:
-248.425 kJ/mol
Explanation:
This question can be done by simply taking the ratios:
Since the given the heat change for 1.00 mol of [tex]CO_2[/tex] is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of
We can write:
[tex]\frac{-373.7} {1.00} = \frac{x}{0.631}[/tex]
[tex]x = ( -373.7)(0.631)[/tex]
[tex]x = -248.425[/tex] KJ/mol