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In the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous for A and the other homozygous for B.

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khubaid

Answer:

In F2 progeny, the phenotypic ratio will be 9/16.

Explanation:

Both A and B genes are dominant and responsible for color of daisy.

Both a and b genes are recessive and daisy will remain colorless.

Each copy of A and B must be required for daisy to be colorful.

When two white flowers are crossed, one homozygous for A and other homozygous for B.

AAbb x aaBB

Result:

According to Punnett square, in F2 progeny, 9 out of 16 daisy will colorful or the ratio will be 9/16.

luisvaschetto

The F2 progeny of a double homo-zygous Parental (P) cross will be colored flowers in a proportion 9/16.

  • A diploid individual inherits two alleles or gene forms for each locus, one from the mother and the other from the father.

  • An individual is homo-zygous when inherits the same allele for a given gene locus, whereas an individual is heterozygous when inherits different alleles for a given gene locus.

  • The F1 progeny of a double homo-zygous Parental (P) cross will produce all heterozygous progeny.

In conclusion, the F2 progeny of a double homo-zygous Parental (P) cross will be colored flowers in a proportion 9/16.

Learn more in:

https://brainly.com/question/3676361

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