The answers for the following questions is answered below.
- Therefore the volume of a gas is 22.4 L
- Therefore the number of moles of oxygen are 2.37 moles
Explanation:
1. Given:
no of molecules (n) = 6.023 × [tex]10^{23}[/tex]
volume of gas at STP conditions (V) =22.4 liters
To solve:
Volume of gas (v)
We know;
[tex]\frac{n}{N_{a} } =\frac{v}{V}[/tex]
[tex]\frac{6.023 * 10^{23} }{6.023 * 10^{23} } =\frac{v}{22.4}[/tex]
1 × 22.4 = v
v =22.4 L
Therefore the volume of a gas is 22.4 L
2. Given:
volume of oxygen gas (v) = 53 L
Volume of gas at STP conditions (V) =22.4 L
To solve:
no of moles of oxygen gas
We know;
[tex]n =\frac{v}{V}[/tex]
n =[tex]\frac{53}{22.4}[/tex]
n =2.37 moles
Therefore the number of moles of oxygen are 2.37 moles
