Answer:
The deflection angle of the compass is 37⁰
Explanation:
[tex]B_{magnet} = B_{Earth}*tan( \theta)\\\\tan( \theta) = \frac{B_{magnet}}{B_{Earth}}[/tex]
Given;
Earth’s magnetic field strength, B = 20μT
Magnetic field strength of the coil, B = 15 µT
Substitute the given values in the equation above and calculate the deflection angle of the compass.
[tex]\tan( \theta) = \frac{15 \mu T}{20 \mu T}\\\\\tan( \theta) = 0.75\\\\\theta = tan^{-1}( 0.75)\\\\\theta = 36.87 =37^o[/tex]
Therefore, the deflection angle of the compass assuming the two magnetic fields are perpendicular to each other is 37⁰
