Answer:
Explanation:
Given that,
Warm temperature TH = 1500°C
K= °C +273
TH=1500+273=1773K
Cold temperature TL = 20°C
TL = 20+273
TL = 293K
The efficiency of a Carnot engine is given as
η = 1 — (TL/TH)
η = 1 — (293/1773)
η = 1 — 0.165
η = 0.8347
Then, in %
η = 0.8347×100
η = 83.47%
Thermal efficiency is 83.47%