Respuesta :
Answer:
0.25% probability that they are both defective
Step-by-step explanation:
For each computer chip, there are only two possible outcomes. Either they are defective, or they are not. The probability of a computer chip being defective is independent of other chips. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
5% of the computer chips it makes are defective.
This means that [tex]p = 0.05[/tex]
If an inspector chooses two computer chips randomly (meaning they are independent from each other), what is the probability that they are both defective?
This is P(X = 2) when n = 2. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025[/tex]
0.25% probability that they are both defective
