length of AB is [tex]\sqrt{11} units[/tex] .
Step-by-step explanation:
Here we have , two points as A(3,- 4, 2) and B(2, -1, 3) . We need to find the length of AB. Let's find out:
We know that , Distance between any two points [tex]P(x_1,y_1,z_1), Q(x_2,y_2,z_2)[/tex] is given by distance formula as :
[tex]Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}[/tex]
Putting A(3,- 4, 2) and B(2, -1, 3) in above formula :
⇒ [tex]Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}[/tex]
⇒ [tex]Distance = \sqrt{(2-3)^2+((-1)-(-4))^2+(3-2)^2}[/tex]
⇒ [tex]Distance = \sqrt{1+9+1}[/tex]
⇒ [tex]Distance = \sqrt{11}[/tex]
Therefore , length of AB is [tex]\sqrt{11} units[/tex] .
