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An object is shot upwards, from the ground, with an initial velocity of 120
m/s. How high will it be after 4.Os?​

Respuesta :

olatunbosunadeoke

Answer: 30 metres

Explanation:

Initial velocity of object = 120m/s

Time taken = 4.0s

Distance covered by object = ?

Recall that distance = (Change in velocity / Time taken)

Distance = (120m/s)/4.0s

= (120m/s) / 4.0s

= 30m

Thus, the object will be 30 metres high

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