Answer:
0.079 m or 79 mm
Explanation:
Using the equation of motion
v = √(2as)
Where v is the velocity
a is acceleration = 1400m/s²
s is the distance = 0.55 mm = 0.00055m
Therefore
= √(2 × 1400m/s² × 0.00055 m) = 1.54 m/s
Therefore; initial velocity = 1.54 m/s
Then we use the equation of motion s = v² / 2g
Take g = 9.8 m/s²
Therefore
= (1.54m/s)² / 19.6 m/s²
= 0.079 m or 79 mm
Answer:
Explanation:
Given:
Acceleration, a = 1400 m/s^2
Distance, s = 0.55 mm
= 0.000055 m
Final velocity, v = 0 m/s
Using equation of motion,
v^2 = u^2 + 2as
u = √(2as)
= √(2 * 1400 × 0.000055)
= 0.8775 m/s
Initial velocity, u = 0.8775 m/s
Finding distance, S at, a = g = 9.8 m/s^2
Using equations of motion above,
S = u²/2g
= (0.8775)²/(2 × 9.8)
= 0.039 m
= 39 mm
