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A uniformly charged conducting plate with area A has a total charge Q which is positive. Consider a cross-sectional view of the plane and the electric field lines due to the charge on the plane. E E +Q + + + + + + + + + + + P Find the magnitude of the field at point P, which is a distance a from the plate. Assume that a is very small when compared to the dimensions of the plate, such that edge effects

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okpalawalter8

Complete Question

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Answer:

The correct answer is option 9

Explanation:

The objective of this question i to obtain the magnitude of the electric field

We are told from the question that

     The area is A

      The magnitude of the total charge is Q

Generally the surface charge density is mathematically represented as

                  [tex]\sigma = \frac{Q}{A}[/tex]

Now the electric field for a uniform conducting plate is mathematically represented as

             [tex]E = \frac{|\sigma| }{2\epsilon_o}[/tex]

Now substituting the formula above for [tex]\sigma[/tex]

             [tex]E = \frac{Q}{2\epsilon_o A}[/tex]

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