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Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?

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TheAnimeGirl

the answer is 15. Hope this will help u.....

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Wallind11

Step-by-step explanation:

The general equation of a circle with center (h,k) and radius r passing through a point (x,y) is given by

[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} [/tex]

Here, r²= {3-(-1)}²+(6-3)²

=( 3+1)²+(3)²

= 16+9

= 25

So, the equation;

{x-(-1)}²+(y-3)²= 25

or,(x+1)²+(y-3)²=25

or, x²+2x+1+y²-6y+9-25=0

or,x²+y²+2x-6y-15=0

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