[tex]y = x -2, x\geq 1[/tex]
Step-by-step explanation:
In the question given correct parameter is - 2) [tex]y = x -2, x\geq 1[/tex]
Method -
[tex]x= t^2 + 1[/tex] ........................(1)
[tex]y = t^2 - 1[/tex] ..........................(2)
Let's solve the equation 1,
⇒ [tex]x = t^2 +1[/tex]
⇒ [tex]t^2 = x - 1[/tex]
- Put the value of t² in equation 2
[tex]y =t^2 - 1 \\y = x -1 -1\\y = x - 2[/tex]
Here we got the y parameter as [tex]y = x -2[/tex]
So the option no .2 is the correct option 2) [tex]y = x -2, x\geq 1[/tex]
