Answer:
DL = 0.0105 [m] = 10.57 [mm]
Explanation:
To solve this problem, we use the following equation that involves length changes depending on temperature changes.
[tex]DL=\alpha *DT*L[/tex]
where:
DL = length change
Ī± = thermal expansion coefficient = 11 * 10^(-6) [1/Ā°C]
DT = temperature change = (37-6) = 31 [Ā°C]
L = nominal or initial Ā length = 31 [m]
DL = 11 * 10^(-6) * 31 * 31
DL = 0.0105 [m] = 10.57 [mm]
