Answer:
50,000 V/m
Explanation:
The electric field between two charged metal plates is uniform.
The relationship between potential difference and electric field strength for a uniform field is given by the equation
[tex]\Delta V=Ed[/tex]
where
[tex]\Delta V[/tex] is the potential difference
E is the magnitude of the electric field
d is the  distance between the plates
In this problem, we have:
[tex]\Delta V=750 V[/tex] is the potential difference between the plates
d = 15 mm = 0.015 m is the distance between the plates
Therefore, rearranging the equation we find the strength of the electric field:
[tex]E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m[/tex]