What value of y will make △DEF ≅ △JKI

Step-by-step explanation:
∆DEF congruent to ∆JKI
FD=JI (corresponding angles of congruent triangles)
z+22= 3z
or,z-3z= -22
or,-2z= -22
or, z= 11
EF=KI(corresponding angles of congruent triangles)
5y+13=6y
y=13
Answer:
z = 11.
y = 13.
Step-by-step explanation:
For congruency 3z = z + 22
2z = 22
z = 11.
Also
5y + 13 = 6y
13 = y.