Answer:
probability that a randomly selected page that contains only text will contain no typos that is
P(x=0) = [tex]e^{-0.08}[/tex] = 0.923
Step-by-step explanation:
Poisson distribution:-
Explanation of the Poisson distribution :-
The Poisson distribution can be derived as a limiting case of the binomial
distribution under the conditions that
i) p is very small
ii) n is very large
ii) λ = np (say finite
The probability of 'r' successes = [tex]\frac{e^{-\alpha }\alpha^r }{r!}[/tex]
Given the average number of typos ∝ = 0.08 per page.
probability that a randomly selected page that contains only text will contain no typos that is = [tex]p(x=0) = \frac{e^{-0.08 }\(-0.08)^0 }{0!}[/tex]
After calculation P(x=0) = [tex]e^{-0.08}[/tex] = 0.923
probability that a randomly selected page that contains only text will contain no typos =0.923