Answer:
Final speeds are equal to each other.
Explanation:
Both objects experiment a change in their velocities because of gravity. Let model each object by following equations:
Object A - Throw Up
[tex]v = -\sqrt{v_{o}^{2}+2\cdot g \cdot h}[/tex]
Object B - Throw Down
[tex]v = -\sqrt{v_{o}^{2}+2\cdot g \cdot h}[/tex]
Where [tex]h[/tex] is the height difference between the top of the building and the street. Let consider upward speed positive.
Final speeds are equal to each other.
The speed when they hit the street will be equal to each other.
A force applied to all bodies on Earth is Weight ( W ), which is caused by Earth's gravity. If a body is free falling, its only acceleration is g , gravity. So gravity increases velocity.
Both objects will show a change in their velocities because of gravity.
The velocity for both objects if one is thrown up and other is thrown down is same which is given by this formula:
[tex]v=-\sqrt{v_0^2 +2.g.h}[/tex]
where, v= final velocity, v₀= initial velocity, h is the difference in height between building and street and g= acceleration due to gravity.
Assuming upward speed to be positive.
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