Which inequalities would have an open circle when graphed? Check all that apply.

It is given that the inequalities.
We need to determine the inequalities which have an open circle.
The graph will have an open circle only if it has the symbol < or > because it indicates that the boundary is not included.
Option A: [tex]t \geq 25[/tex]
The inequality shows that it contains the boundary point 25.
Hence, the inequality [tex]t \geq 25[/tex] does not have an open circle.
Hence, Option A is not the correct answer.
Option B: [tex]-2.5 \leq m[/tex]
The inequality shows that it contains the boundary point -2.5.
Hence, the inequality [tex]-2.5 \leq m[/tex] does not have an open circle.
Hence, Option B is not the correct answer.
Option C: [tex]x>5.4[/tex]
The inequality shows that it does not contains the boundary point 5.4
Hence, the inequality [tex]x>5.4[/tex] have an open circle.
Thus, Option C is the correct answer.
Option D: [tex]\frac{1}{2}>x[/tex]
The inequality shows that it does not contain the boundary point [tex]\frac{1}{2}[/tex]
Hence, the inequality [tex]\frac{1}{2}>x[/tex] have an open circle.
Thus, Option D is the correct answer.
Option E: [tex]x>0[/tex]
The inequality shows that it does not contain the boundary point 0
Hence, the inequality [tex]x>0[/tex] have an open circle.
Thus, Option E is the correct answer.
Answer:
x > 5.4
One-half less-than x
x > 0
these are correct C D E
Step-by-step explanation: