Respuesta :
Answer : The concentration of [tex]NH_3[/tex] in the solution is, [tex]2.94\times 10^{-4}M[/tex]
Explanation :
First we have to calculate the volume of aqueous solution that is water.
Density of water = 1.00 g/mL
Mass of water = 2400 g
[tex]\text{Volume of water}=\frac{Mass}{Density}=\frac{2400g}{1.00g/mL}=2400mL[/tex]
Now we have to calculate the concentration of ammonia solution.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }NH_3\times 1000}{\text{Molar mass of }NH_3\times \text{Volume of solution (in mL)}}[/tex]
Molar mass of [tex]NH_3[/tex] = 17 g/mole
Now put all the given values in this formula, we get:
[tex]\text{Molarity}=\frac{0.012g\times 1000}{17g/mole\times 2400mL}=3.12mole/L=2.94\times 10^{-4}M[/tex]
Therefore, the concentration of [tex]NH_3[/tex] in the solution is, [tex]2.94\times 10^{-4}M[/tex]
