What is the m∠J, to the nearest tenth?

Answer:
Have to do a^2 plus b^2 =c^2
Step-by-step explanation:
Answer:
<J = 58.1
Step-by-step explanation:
tan theta = opp / adjacent sides
tan J = 15.1/9.4
Take the inverse tan of each side
tan ^-1 (tan J) = tan^-1 (15.1/9.4)
J= 58.09705252
Rounding to the nearest tenth
J = 58.1