Answer:
100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.
Explanation:
Heat = mass * lf
Latent heat of fusion (lf) of water is 334J/g
Heat = 300g * 334 J/g
Heat = 100,200J of heat
Answer:
100800 J
Explanation:
Specific Latent heat of fusion of water: This is the quantity of heat required to change the unit mass of water from ice to liquid without change in temperature.
The expression for Specific latent heat of fusion is given as
Q = Cm...................... Equation 1
Where Q = Amount of heat, C = Specific latent heat of fusion of ice, m = mass of ice.
Given: m = 0.3 kg,
Constant: C = 336000 J/kg
substitute into equation 1
Q = 336000(0.3)
Q = 100800 J.
