Answer : The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
[tex]\Delta G^o=-RT\times \ln Q\\\\\Delta G^o=-RT\times \ln (\frac{[A]_{inside}}{[A]_{outside}})[/tex]
where,
[tex]\Delta G^o[/tex] = standard Gibbs free energy = -14.1 kJ/mol
R = gas constant = 8.314 J/K.mol
T = temperature = [tex]25^oC=273+25=298K[/tex]
Q = reaction quotient
[tex][A]_{inside}[/tex] = concentration inside the cell
[tex][A]_{outside}[/tex] = concentration outside the cell
Now put all the given values in the above formula, we get:
[tex]-14.1\times 10^3J/mol =-(8.314J/K.mol)\times (298K)\times \ln (\frac{[A]_{inside}}{[A]_{outside}})[/tex]
[tex]\frac{[A]_{inside}}{[A]_{outside}}=296.2[/tex]
Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2