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Two cars are raised to the same elevation on service- station lifts. If one car is twice as massive as the other, how do their potential energies compare?

Respuesta :

adelekeademolu

Answer:

The potential energy of the more massive one is twice that of the other.

Explanation:

Potential energy is given by

PE = mgh

where m = mass of body, g = acceleration of gravity and h = height or elevation.

For the less massive car, let the mass be [tex]m_1[/tex]. Then its PE is

[tex]PE_1 = m_1gh[/tex]

For the massive car, let the mass be [tex]m_2[/tex].  Its PE is

[tex]PE_2 = m_2gh[/tex]

But [tex]m_2 =2m_1[/tex]

[tex]\therefore PE_2 = 2m_1gh = 2(m_1gh) = 2PE_1[/tex]

Hence, the potential energy of the more massive one is twice that of the other.

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